Accuracy Example AD2

[zja62]

Hello,

I would like to walk an example for the expected accuracy worst case on the AD2. 

Listed accuracy (scale ≥1V/div, VinCM = 0V): +/-100mV +/-0.5%

So 1V/div, would be 1V +/- .105V or 10.5%?

Likewise,

Listed accuracy (scale ≤0.5V/div, VinCM = 0V): +/- 10 mV+/-0.5%

So .1V/div, would be .1V +/-.0105V or 10.5%

 

Please correct my understanding if I don't have this right. 

[JColvin]

Hi @zja62,

It is +/- 10 mV offset error and +/- 0.5% of the actual value. So for 1V, it would be between 0.985 V to 1.015 V. There are some more details about this same topic on this Forum thread here:

Let me know if you have any questions.

Thanks,
JColvin