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Hello, I would like to walk an example for the expected accuracy worst case on the AD2. Listed accuracy (scale ≥1V/div, VinCM = 0V): +/-100mV +/-0.5% So 1V/div, would be 1V +/- .105V or 10.5%? Likewise, Listed accuracy (scale ≤0.5V/div, VinCM = 0V): +/- 10 mV+/-0.5% So .1V/div, would be .1V +/-.0105V or 10.5% Please correct my understanding if I don't have this right.