Jump to content

Lwin D

Members
  • Posts

    2
  • Joined

  • Last visited

Lwin D's Achievements

Newbie

Newbie (1/4)

0

Reputation

  1. Hi @Nick Wright, thank you for your response. One quick question, how do I calculate the CJC voltage given the thermocouple type and an ambient temperature of ~20 C? Do I just find the corresponding thermocouple voltage for 20 C for J and C type thermocouples?
  2. Hello, I am interested in using a C-type thermocouple for high temperature measurements. Our thermocouple DAQ, Measurement Computing's USB-TC, cannot directly interface with C-type thermocouples (it is not of one of the included settings), but I wanted to try and back-door it with the following method: Connect the C-type thermocouple to one of USB-TC's thermocouple channels (for example, channel 0) Set Channel 0's thermocouple type to a thermocouple type with a similar EMF/voltage range as C-types, such as K or J-types (see below figure of thermocouple output voltage to temperature) Set Channel 0 to read out not as a temperature, but as a voltage reading (I can accomplish this with Measurement Computing's python package, mcculw) Convert Channel 0's read out voltage to a temperature using NIST's chart for thermocouple voltage to temperature for C-types (link: https://sea.omega.com/temperature/Z/pdf/z239-240.pdf) Currently, my main concern is how to account for the reference junction temperature in the conversion of Channel 0's stated voltage and the final C-type thermocouple temperature, assuming the reference junction is at 20 C. From the USB-TC's manual, I understand that the DAQ automatically corrects for the cold junction compensation by subtracting it from the analog input's thermocouple voltage measurement. However, is this correction performed when I set Channel 0 to read out voltages rather than temperatures? If not, how do I calculate the cold junction compensation voltage myself? Finally, are there other inaccuracies/obstacles that I should consider that might make this C-type measurement impossible/not useful? Thank you in advance for any and all advice.
×
×
  • Create New...