Inquiry About Default States and Voltages for AD2 Static Digital I/O Pins

[Juan05]

Hello,

I'm working with the Analog Discovery 2 and have some questions regarding the behavior of its digital I/O pins. I've read through the specifications, but some details about the default states and voltage levels are still unclear to me, both from an SDK perspective and while using WaveForms. Here are my specific questions:

What is the default state of the digital pins when they are first enabled? Are they set to a low state, high state, or are they in high-impedance mode?

What happens to the pins when they are disabled? Do they default to a specific voltage, or do they go to high-impedance mode?

I'm trying to understand the logic levels for proper interfacing and to ensure I'm not causing any unintended shorts or placing incorrect loads on the pins. Any insights, especially regarding the default enabled and disabled states, would be greatly appreciated.

Thank you in advance for your assistance!

[attila]

Hi @Juan05

By default the DIOs are in high impedance. These can be controlled to drive low/high/Z by the digital-out and digital-io functions.
Before the device is powered up the DIOs are pulled to GND by the protection circuit.